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2N4444 View Datasheet(PDF) – Motorola => Freescale
If we take 3mA to be very safe, the voltages balance out but we have to live with the high leakage current through the load, which may be a problem for the application.
In the diagram I used a leakage for 10uA for the one and about 20uA for the other.
Anyone out there with any experience in this application??? By stanyJune 3, in Power Electronics. We connect dattasheet as shown in the first diagram, but find that the load turns on when we connect the power, even with no trigger applied. I have a project coming up where I need to hold off about volts using an SCR.
Create an account or sign in to comment You need to be a member in order to leave a comment Create an account Sign up for a new account in our community. Sign In Sign Up. Look at this AP-note http: Also note that we will be generating a fair amount of heat in the balancing resistors as shown on the wattmeter.
This will cause voltage breakdown of D1, followed by breakdown of D2. Posted June 6, Sign up for a new account in our community.
We want to use it in a V application. Years ago, I read or heard of someone putting two SCR’s in series to achieve higher voltage rating. Posted June 4, Power Electronics Search In. Already have an account?
2N 데이터시트(PDF) – Motorola, Inc
Register a new account. From what I have seen they use pulse transformers to trig from a lower voltage to achieve simultaneous response.
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PDF This gives you the basic idea, but there are other problem issues not mentioned here. Let’s look at a typical hookup using two 2N’s in series. Sign in Already have an account?
We need to create a additional leakage path greater that the worst leakage spec in order to balance the voltages. We can see that D1 with the lowest leakage will have more than its rated V over it.
The problem is the leakage current that may vary from 10uA at a cold junction temperature to 2mA for a hot junction.
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Posted June 3, A single device with this type of holdoff is really expensive, dataxheet I’m looking for an alternative solution. Hey guys, I’m a new member to this forum, so I have no idea if this topic has arisen before. Off my head, I cant just ramble out the way it works, but I’ll look through the schematics and the theory book tommorow at work and try to get you a more definitive answer.